What is the general solution for cos(θ)= 20/29 ?

The general solution for cos(θ)= 20/29 is θ=0.80978…+2pin,θ=2pi-0.80978…+2pin

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cos(θ)= 20/29

cos (θ) = \frac{20}{29}

θ = 0.80978 \dots + 2 πn, θ = 2 π - 0.80978 \dots + 2 πn

Degrees

θ = 46.39718 \dots^{\circ} + 36 0^{\circ} n, θ = 313.60281 \dots^{\circ} + 36 0^{\circ} n

Solution steps

cos (θ) = \frac{20}{29}

Apply trig inverse properties

cos (θ) = \frac{20}{29}

General solutions for

cos (θ) = \frac{20}{29}

cos (x) = a \Rightarrow x = arccos (a) + 2 πn, x = 2 π - arccos (a) + 2 πn

θ = arccos (\frac{20}{29}) + 2 πn, θ = 2 π - arccos (\frac{20}{29}) + 2 πn

θ = arccos (\frac{20}{29}) + 2 πn, θ = 2 π - arccos (\frac{20}{29}) + 2 πn

Show solutions in decimal form

θ = 0.80978 \dots + 2 πn, θ = 2 π - 0.80978 \dots + 2 πn

- cos^{2} (θ) + sin^{2} (θ) = 1 + cos (θ)

sin (x) - 3 cos (x) = 1

tan (x) = 0.4

sin^{3} (t) = sin (t)

tan^{2} (x) + 3 = 4 tan (x)

What is the general solution for cos(θ)= 20/29 ?
The general solution for cos(θ)= 20/29 is θ=0.80978…+2pin,θ=2pi-0.80978…+2pin