What is the general solution for solvefor y,x=sqrt(sin(y)) ?

The general solution for solvefor y,x=sqrt(sin(y)) is y=arcsin(x^2)+2pin,y=pi+arcsin(-x^2)+2pin

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solvefor y,x=sqrt(sin(y))

solve for

y, x = sin (y)

y = arcsin (x^{2}) + 2 πn, y = π + arcsin (- x^{2}) + 2 πn

Solution steps

x = sin (y)

Switch sides

sin (y) = x

Square both sides:

sin (y) = x^{2}

sin (y) = x^{2}

Verify Solutions:

sin (y) = x^{2} {x \geq 0}

The solution is

sin (y) = x^{2} {x \geq 0}

Apply trig inverse properties

y = arcsin (x^{2}) + 2 πn, y = π + arcsin (- x^{2}) + 2 πn

sin (x) + sin (x) cos (x) = 0

tan (x) = \frac{5}{5}

sin (θ) cos (θ) = 0

csc (θ) = \frac{1}{2}

sin (θ) = \frac{3}{2}

What is the general solution for solvefor y,x=sqrt(sin(y)) ?
The general solution for solvefor y,x=sqrt(sin(y)) is y=arcsin(x^2)+2pin,y=pi+arcsin(-x^2)+2pin