What is the general solution for 2sin(θ)=cos(θ) ?

The general solution for 2sin(θ)=cos(θ) is θ=0.46364…+pin

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

2sin(θ)=cos(θ)

2 sin (θ) = cos (θ)

θ = 0.46364 \dots + πn

Solution steps

2 sin (θ) = cos (θ)

Rewrite using trig identities

2 tan (θ) = 1

Divide both sides by

2

tan (θ) = \frac{1}{2}

Apply trig inverse properties

θ = arctan (\frac{1}{2}) + πn

Show solutions in decimal form

θ = 0.46364 \dots + πn

2 cos (x) = - 1

2 sec (u) sin (u) + 2 = 4 sin (u) + sec (u)

4 cos^{2} (x) - 1 = 0, 0 \leq x < 2 π

y, e^{2 x} = sin (x + 3 y)

7 sin (2 x) = 7 cos (x)

What is the general solution for 2sin(θ)=cos(θ) ?
The general solution for 2sin(θ)=cos(θ) is θ=0.46364…+pin