What is the general solution for 2cos(2θ)-sqrt(3)=0 ?

The general solution for 2cos(2θ)-sqrt(3)=0 is θ= pi/(12)+pin,θ=(11pi)/(12)+pin

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2cos(2θ)-sqrt(3)=0

2 cos (2 θ) - 3 = 0

θ = \frac{π}{12} + πn, θ = \frac{11 π}{12} + πn

Solution steps

2 cos (2 θ) - 3 = 0

Move

3

to the right side

2 cos (2 θ) = 3

Divide both sides by

2

cos (2 θ) = \frac{3}{2}

General solutions for

cos (2 θ) = \frac{3}{2}

2 θ = \frac{π}{6} + 2 πn, 2 θ = \frac{11 π}{6} + 2 πn

Solve

2 θ = \frac{π}{6} + 2 πn : θ = \frac{π}{12} + πn

Solve

2 θ = \frac{11 π}{6} + 2 πn : θ = \frac{11 π}{12} + πn

θ = \frac{π}{12} + πn, θ = \frac{11 π}{12} + πn

3 arccos (4 x) = 2 π

cos (3 x) = cos (x)

tan (x + 3 2^{\circ}) = cot (x - 2 0^{\circ})

cosh (z) = - 1

0 = sin (2 θ)

What is the general solution for 2cos(2θ)-sqrt(3)=0 ?
The general solution for 2cos(2θ)-sqrt(3)=0 is θ= pi/(12)+pin,θ=(11pi)/(12)+pin