What is the general solution for sin(x)-1/2 =0 ?

The general solution for sin(x)-1/2 =0 is x= pi/6+2pin,x=(5pi)/6+2pin

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sin(x)-1/2 =0

sin (x) - \frac{1}{2} = 0

x = \frac{π}{6} + 2 πn, x = \frac{5 π}{6} + 2 πn

Solution steps

sin (x) - \frac{1}{2} = 0

Move

\frac{1}{2}

to the right side

sin (x) = \frac{1}{2}

General solutions for

sin (x) = \frac{1}{2}

x = \frac{π}{6} + 2 πn, x = \frac{5 π}{6} + 2 πn

4 cos^{2} (x) = 3 - 4 cos (x)

sin (x) = 0.32

cos^{4} (x) + sin^{4} (x) = 1

sin^{2} (x) + 3 cos^{2} (x) = 0

sec^{2} (\frac{x}{2}) = 2

What is the general solution for sin(x)-1/2 =0 ?
The general solution for sin(x)-1/2 =0 is x= pi/6+2pin,x=(5pi)/6+2pin