What is the general solution for -6sin(θ)-3=sin(θ)+4 ?

The general solution for -6sin(θ)-3=sin(θ)+4 is θ=(3pi)/2+2pin

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-6sin(θ)-3=sin(θ)+4

- 6 sin (θ) - 3 = sin (θ) + 4

θ = \frac{3 π}{2} + 2 πn

Solution steps

- 6 sin (θ) - 3 = sin (θ) + 4

Solve by substitution

sin (θ) = - 1

sin (θ) = - 1 : θ = \frac{3 π}{2} + 2 πn

Combine all the solutions

θ = \frac{3 π}{2} + 2 πn

- 9 cos^{2} (θ) + 23 sin (θ) + 17 = - 2

24 arcsin (x) = 4 π

cos (x) - 1 = sin (x)

2 cos^{2} (x) + 3 sin (x) - 3 = 0, 0^{\circ} \leq x \leq 36 0^{\circ}

5 cot (θ) + 7 = 0

What is the general solution for -6sin(θ)-3=sin(θ)+4 ?
The general solution for -6sin(θ)-3=sin(θ)+4 is θ=(3pi)/2+2pin