What is the general solution for 3cos(2x)=0 ?

The general solution for 3cos(2x)=0 is x= pi/4+pin,x=(3pi)/4+pin

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3cos(2x)=0

3 cos (2 x) = 0

x = \frac{π}{4} + πn, x = \frac{3 π}{4} + πn

Solution steps

3 cos (2 x) = 0

Divide both sides by

3

cos (2 x) = 0

General solutions for

cos (2 x) = 0

2 x = \frac{π}{2} + 2 πn, 2 x = \frac{3 π}{2} + 2 πn

Solve

2 x = \frac{π}{2} + 2 πn : x = \frac{π}{4} + πn

Solve

2 x = \frac{3 π}{2} + 2 πn : x = \frac{3 π}{4} + πn

x = \frac{π}{4} + πn, x = \frac{3 π}{4} + πn

3 cos (x) - 3 sin (x) = 0

sin^{3} (x) = 3 sin (x) - 4 sin^{3} (x)

tan (θ) = \frac{2}{3 + 2 cos ( 4 5 ^{\circ} )}

cos (2 θ) + 6 cos^{2} (θ) = 5

sin (4 x) = - \frac{2}{2}

What is the general solution for 3cos(2x)=0 ?
The general solution for 3cos(2x)=0 is x= pi/4+pin,x=(3pi)/4+pin