What is the general solution for tan^2(x)-2tan(x)+1=0 ?

The general solution for tan^2(x)-2tan(x)+1=0 is x= pi/4+pin

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tan^2(x)-2tan(x)+1=0

tan^{2} (x) - 2 tan (x) + 1 = 0

x = \frac{π}{4} + πn

Solution steps

tan^{2} (x) - 2 tan (x) + 1 = 0

Solve by substitution

tan (x) = 1

tan (x) = 1 : x = \frac{π}{4} + πn

Combine all the solutions

x = \frac{π}{4} + πn

sin^{2} (x) - 2 cos^{2} (x) = 1

sin (x) = - \frac{12}{13}

2 sin^{2} (x) + 7 sin (x) - 4 = 0

cos (\frac{5 π}{4} + x) + sin (\frac{5 π}{4} - x) = 0

cos (2 x) + sin (2 x) = 1

What is the general solution for tan^2(x)-2tan(x)+1=0 ?
The general solution for tan^2(x)-2tan(x)+1=0 is x= pi/4+pin