What is the general solution for cos(2x)=0,0<= x<= 2pi ?

The general solution for cos(2x)=0,0<= x<= 2pi is x= pi/4 ,x=(3pi)/4 ,x=(5pi)/4 ,x=(7pi)/4

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cos(2x)=0,0<= x<= 2pi

cos (2 x) = 0, 0 \leq x \leq 2 π

x = \frac{π}{4}, x = \frac{3 π}{4}, x = \frac{5 π}{4}, x = \frac{7 π}{4}

Solution steps

cos (2 x) = 0, 0 \leq x \leq 2 π

General solutions for

cos (2 x) = 0

2 x = \frac{π}{2} + 2 πn, 2 x = \frac{3 π}{2} + 2 πn

Solve

2 x = \frac{π}{2} + 2 πn : x = \frac{π}{4} + πn

Solve

2 x = \frac{3 π}{2} + 2 πn : x = \frac{3 π}{4} + πn

x = \frac{π}{4} + πn, x = \frac{3 π}{4} + πn

Solutions for the range

0 \leq x \leq 2 π

x = \frac{π}{4}, x = \frac{3 π}{4}, x = \frac{5 π}{4}, x = \frac{7 π}{4}

cot^{2} (θ) - csc (θ) = 1

cos (\frac{x}{2}) = - \frac{3}{2}

tan (x) = 0.2

sin (2 t) + sin (t) = 0

2 sin^{2} (x) = 3 (cos (x) + 1)

What is the general solution for cos(2x)=0,0<= x<= 2pi ?
The general solution for cos(2x)=0,0<= x<= 2pi is x= pi/4 ,x=(3pi)/4 ,x=(5pi)/4 ,x=(7pi)/4