What is the general solution for 6cos(θ)+3=0 ?

The general solution for 6cos(θ)+3=0 is θ=(2pi)/3+2pin,θ=(4pi)/3+2pin

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6cos(θ)+3=0

6 cos (θ) + 3 = 0

θ = \frac{2 π}{3} + 2 πn, θ = \frac{4 π}{3} + 2 πn

Solution steps

6 cos (θ) + 3 = 0

Move

3

to the right side

6 cos (θ) = - 3

Divide both sides by

6

cos (θ) = - \frac{1}{2}

General solutions for

cos (θ) = - \frac{1}{2}

θ = \frac{2 π}{3} + 2 πn, θ = \frac{4 π}{3} + 2 πn

sin^{2} (x) + 5 sin (x) + 6 = 0

- 6 tan^{2} (θ) + 11 tan (θ) - 6 = - 2 tan (θ)

(sin (x) + 1)^{2} + cos^{2} (x) = 2

12 sin^{2} (x) - cos (x) - 6 = 0

tan (\frac{x}{2}) - 1 = 0

What is the general solution for 6cos(θ)+3=0 ?
The general solution for 6cos(θ)+3=0 is θ=(2pi)/3+2pin,θ=(4pi)/3+2pin