What is the general solution for 2cos^2(t)-cos(t)=1 ?

The general solution for 2cos^2(t)-cos(t)=1 is t=2pin,t=(2pi)/3+2pin,t=(4pi)/3+2pin

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2cos^2(t)-cos(t)=1

2 cos^{2} (t) - cos (t) = 1

t = 2 πn, t = \frac{2 π}{3} + 2 πn, t = \frac{4 π}{3} + 2 πn

Solution steps

2 cos^{2} (t) - cos (t) = 1

Solve by substitution

cos (t) = 1, cos (t) = - \frac{1}{2}

cos (t) = 1 : t = 2 πn

cos (t) = - \frac{1}{2} : t = \frac{2 π}{3} + 2 πn, t = \frac{4 π}{3} + 2 πn

Combine all the solutions

t = 2 πn, t = \frac{2 π}{3} + 2 πn, t = \frac{4 π}{3} + 2 πn

- 2 sin (t) + cos (2 t) \cdot 2 = 0

tan (a) = \frac{4}{3}

5 sin (θ) - 1 = 0

tan (x) csc (x) - tan (x) = 0

cos (6 0^{\circ} - x) = sin (70 - 3 x)

What is the general solution for 2cos^2(t)-cos(t)=1 ?
The general solution for 2cos^2(t)-cos(t)=1 is t=2pin,t=(2pi)/3+2pin,t=(4pi)/3+2pin