What is the general solution for cos(1/x)=0 ?

The general solution for cos(1/x)=0 is x= 2/(pi(1+4n)),x= 2/(pi(3+4n));\quad n\ne-1/4 ,n\ne-3/4

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cos(1/x)=0

cos (\frac{1}{x}) = 0

x = \frac{2}{π ( 1 + 4 n )}, x = \frac{2}{π ( 3 + 4 n )}; n \neq = - \frac{1}{4}, n \neq = - \frac{3}{4}

Solution steps

cos (\frac{1}{x}) = 0

General solutions for

cos (\frac{1}{x}) = 0

\frac{1}{x} = \frac{π}{2} + 2 πn, \frac{1}{x} = \frac{3 π}{2} + 2 πn

Solve

\frac{1}{x} = \frac{π}{2} + 2 πn : x = \frac{2}{π ( 1 + 4 n )}; n \neq = - \frac{1}{4}

Solve

\frac{1}{x} = \frac{3 π}{2} + 2 πn : x = \frac{2}{π ( 3 + 4 n )}; n \neq = - \frac{3}{4}

x = \frac{2}{π ( 1 + 4 n )}, x = \frac{2}{π ( 3 + 4 n )}; n \neq = - \frac{1}{4}, n \neq = - \frac{3}{4}

y, x = sinh (y)

- 3 cos (2 θ) + cos (θ) - 10 = - 6 cos (θ) - 5

7 cot (θ) = 3 csc (θ)

5 sin (x) = 2

4 (cot (θ) + 1) = 2 (cot (θ) + 2)

What is the general solution for cos(1/x)=0 ?
The general solution for cos(1/x)=0 is x= 2/(pi(1+4n)),x= 2/(pi(3+4n));\quad n\ne-1/4 ,n\ne-3/4