What is the general solution for 2sin^2(x)-cos(x)+1=0 ?

The general solution for 2sin^2(x)-cos(x)+1=0 is x=2pin

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

2sin^2(x)-cos(x)+1=0

2 sin^{2} (x) - cos (x) + 1 = 0

x = 2 πn

Solution steps

2 sin^{2} (x) - cos (x) + 1 = 0

Rewrite using trig identities

3 - cos (x) - 2 cos^{2} (x) = 0

Solve by substitution

cos (x) = - \frac{3}{2}, cos (x) = 1

cos (x) = - \frac{3}{2} :

No Solution

cos (x) = 1 : x = 2 πn

Combine all the solutions

x = 2 πn

sin (θ) = - 0.4

sin (θ) = - 0.2

6 cos (2 x) = 5

2 cos^{2} (2 x) = 1

sin (z) = \frac{1}{2}

What is the general solution for 2sin^2(x)-cos(x)+1=0 ?
The general solution for 2sin^2(x)-cos(x)+1=0 is x=2pin