What is the general solution for cos(θ)=0.3,0<= θ<= 2pi ?

The general solution for cos(θ)=0.3,0<= θ<= 2pi is θ=1.26610…,θ=5.01708…

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cos(θ)=0.3,0<= θ<= 2pi

cos (θ) = 0.3, 0 \leq θ \leq 2 π

θ = 1.26610 \dots, θ = 5.01708 \dots

Solution steps

cos (θ) = 0.3, 0 \leq θ \leq 2 π

Apply trig inverse properties

θ = arccos (0.3) + 2 πn, θ = 2 π - arccos (0.3) + 2 πn

Solutions for the range

0 \leq θ \leq 2 π

θ = 1.26610 \dots, θ = 5.01708 \dots

cos (3 x) = - \frac{2}{2}

2 cos (x) + 1 = 2

sin (θ) = \frac{5}{9}

1 + sin (x) = 2 sin^{2} (x)

sec (x) = 2 csc (x)

What is the general solution for cos(θ)=0.3,0<= θ<= 2pi ?
The general solution for cos(θ)=0.3,0<= θ<= 2pi is θ=1.26610…,θ=5.01708…