What is the general solution for 13cos(x)+7=-cos(x) ?

The general solution for 13cos(x)+7=-cos(x) is x=(2pi)/3+2pin,x=(4pi)/3+2pin

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13cos(x)+7=-cos(x)

13 cos (x) + 7 = - cos (x)

x = \frac{2 π}{3} + 2 πn, x = \frac{4 π}{3} + 2 πn

Solution steps

13 cos (x) + 7 = - cos (x)

Solve by substitution

cos (x) = - \frac{1}{2}

cos (x) = - \frac{1}{2} : x = \frac{2 π}{3} + 2 πn, x = \frac{4 π}{3} + 2 πn

Combine all the solutions

x = \frac{2 π}{3} + 2 πn, x = \frac{4 π}{3} + 2 πn

cos^{2} (x) = 0.25

2 sin (x) + \frac{3}{2} = sin (x)

3 tan (2 x) = 3

12 cos^{2} (x) = 3

2 cos (x) - 2 sin (x) = 1, 0 \leq x < 2 π

What is the general solution for 13cos(x)+7=-cos(x) ?
The general solution for 13cos(x)+7=-cos(x) is x=(2pi)/3+2pin,x=(4pi)/3+2pin