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Popular >

2sin(2θ)+sqrt(3)=0

Solution

2 sin (2 θ) + 3 = 0

Solution

θ = \frac{2 π}{3} + πn, θ = \frac{5 π}{6} + πn

+1

Solution steps

2 sin (2 θ) + 3 = 0

Move

3

to the right side

2 sin (2 θ) = - 3

Divide both sides by

2

sin (2 θ) = - \frac{3}{2}

General solutions for

sin (2 θ) = - \frac{3}{2}

2 θ = \frac{4 π}{3} + 2 πn, 2 θ = \frac{5 π}{3} + 2 πn

Solve

2 θ = \frac{4 π}{3} + 2 πn : θ = \frac{2 π}{3} + πn

Solve

2 θ = \frac{5 π}{3} + 2 πn : θ = \frac{5 π}{6} + πn

θ = \frac{2 π}{3} + πn, θ = \frac{5 π}{6} + πn

Popular Examples

sin^2(x)+4sin(x)+3=0

sin^{2} (x) + 4 sin (x) + 3 = 0

cos^2(x)-sin^2(x)=(sqrt(2))/2

cos^{2} (x) - sin^{2} (x) = \frac{2}{2}

4cos(2θ)+3cos(θ)+4=-3cos(θ)-1

4 cos (2 θ) + 3 cos (θ) + 4 = - 3 cos (θ) - 1

cos(θ-pi/4)-1=0

cos (θ - \frac{π}{4}) - 1 = 0

solvefor x,-sin(x)=0 solve for

x, - sin (x) = 0

Frequently Asked Questions (FAQ)

What is the general solution for 2sin(2θ)+sqrt(3)=0 ?
The general solution for 2sin(2θ)+sqrt(3)=0 is θ=(2pi)/3+pin,θ=(5pi)/6+pin