What is the general solution for tan(θ)=-(sqrt(3))/2 ?

The general solution for tan(θ)=-(sqrt(3))/2 is θ=-0.71372…+pin

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tan(θ)=-(sqrt(3))/2

tan (θ) = - \frac{3}{2}

θ = - 0.71372 \dots + πn

Degrees

θ = - 40.89339 \dots^{\circ} + 18 0^{\circ} n

Solution steps

tan (θ) = - \frac{3}{2}

Apply trig inverse properties

tan (θ) = - \frac{3}{2}

General solutions for

tan (θ) = - \frac{3}{2}

tan (x) = - a \Rightarrow x = arctan (- a) + πn

θ = arctan (- \frac{3}{2}) + πn

θ = arctan (- \frac{3}{2}) + πn

Show solutions in decimal form

θ = - 0.71372 \dots + πn

2 cos (2 x) cos (x) + 2 sin (2 x) sin (x) = - 1

5 cos (3 x) = 4

tan (\frac{θ}{2} + \frac{π}{4}) = - 1

2 cos^{2} (θ) - 11 cos (θ) + 5 = 0

4 sin (2 x) - 1 = 0

What is the general solution for tan(θ)=-(sqrt(3))/2 ?
The general solution for tan(θ)=-(sqrt(3))/2 is θ=-0.71372…+pin