What is the general solution for tan^2(x)-sqrt(3)tan(x)=0,0<= x<2pi ?

The general solution for tan^2(x)-sqrt(3)tan(x)=0,0<= x<2pi is x= pi/3 ,x=(4pi)/3 ,x=0,x=pi

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tan^2(x)-sqrt(3)tan(x)=0,0<= x<2pi

tan^{2} (x) - 3 tan (x) = 0, 0 \leq x < 2 π

x = \frac{π}{3}, x = \frac{4 π}{3}, x = 0, x = π

Solution steps

tan^{2} (x) - 3 tan (x) = 0, 0 \leq x < 2 π

Solve by substitution

tan (x) = 3, tan (x) = 0

tan (x) = 3, 0 \leq x < 2 π : x = \frac{π}{3}, x = \frac{4 π}{3}

tan (x) = 0, 0 \leq x < 2 π : x = 0, x = π

Combine all the solutions

x = \frac{π}{3}, x = \frac{4 π}{3}, x = 0, x = π

tan (θ) = 10

8 sin (θ) - 5 = 3 sin (θ)

2 cos (4 x) + 3 = 0

cos (θ) = 0.4

3 tan (\frac{x}{2}) + 1 = 0

What is the general solution for tan^2(x)-sqrt(3)tan(x)=0,0<= x<2pi ?
The general solution for tan^2(x)-sqrt(3)tan(x)=0,0<= x<2pi is x= pi/3 ,x=(4pi)/3 ,x=0,x=pi