What is the general solution for 2cos^2(x)-1=0,0<= x<= 2pi ?

The general solution for 2cos^2(x)-1=0,0<= x<= 2pi is x= pi/4 ,x=(7pi)/4 ,x=(3pi)/4 ,x=(5pi)/4

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2cos^2(x)-1=0,0<= x<= 2pi

2 cos^{2} (x) - 1 = 0, 0 \leq x \leq 2 π

x = \frac{π}{4}, x = \frac{7 π}{4}, x = \frac{3 π}{4}, x = \frac{5 π}{4}

Solution steps

2 cos^{2} (x) - 1 = 0, 0 \leq x \leq 2 π

Solve by substitution

cos (x) = \frac{1}{2}, cos (x) = - \frac{1}{2}

cos (x) = \frac{1}{2}, 0 \leq x \leq 2 π : x = \frac{π}{4}, x = \frac{7 π}{4}

cos (x) = - \frac{1}{2}, 0 \leq x \leq 2 π : x = \frac{3 π}{4}, x = \frac{5 π}{4}

Combine all the solutions

x = \frac{π}{4}, x = \frac{7 π}{4}, x = \frac{3 π}{4}, x = \frac{5 π}{4}

sin (θ) = 0.82

tan (x) = \frac{1}{10}

cos^{2} (2 x) + 1 + sin (2 x) = 2

8 sin^{2} (x) 2 cos (x) = 7, 0 \leq x \leq 2 π

2 sin^{2} (x) - sin (x) + 3 = 4

What is the general solution for 2cos^2(x)-1=0,0<= x<= 2pi ?
The general solution for 2cos^2(x)-1=0,0<= x<= 2pi is x= pi/4 ,x=(7pi)/4 ,x=(3pi)/4 ,x=(5pi)/4