What is the general solution for sqrt(3)sin(θ)=-cos(θ) ?

The general solution for sqrt(3)sin(θ)=-cos(θ) is θ=(5pi)/6+pin

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sqrt(3)sin(θ)=-cos(θ)

3 sin (θ) = - cos (θ)

θ = \frac{5 π}{6} + πn

Solution steps

3 sin (θ) = - cos (θ)

Rewrite using trig identities

3 tan (θ) = - 1

Divide both sides by

3

tan (θ) = - \frac{3}{3}

General solutions for

tan (θ) = - \frac{3}{3}

θ = \frac{5 π}{6} + πn

- 2 sin (x) + 1 = 0

sin (2 θ) = - \frac{3}{2}, 0 \leq θ \leq 2 π

2 - 2 cos^{2} (\frac{x}{2}) = 2 sin^{2} (x)

3 tanh^{2} (x) = 5 sech (x) + 1

tan (θ) = \frac{5}{7}

What is the general solution for sqrt(3)sin(θ)=-cos(θ) ?
The general solution for sqrt(3)sin(θ)=-cos(θ) is θ=(5pi)/6+pin