What is the general solution for cos(2θ-pi/2)=(sqrt(2))/2 ?

The general solution for cos(2θ-pi/2)=(sqrt(2))/2 is θ=pin+(3pi)/8 ,θ=pin+(9pi)/8

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cos(2θ-pi/2)=(sqrt(2))/2

cos (2 θ - \frac{π}{2}) = \frac{2}{2}

θ = πn + \frac{3 π}{8}, θ = πn + \frac{9 π}{8}

Solution steps

cos (2 θ - \frac{π}{2}) = \frac{2}{2}

General solutions for

cos (2 θ - \frac{π}{2}) = \frac{2}{2}

2 θ - \frac{π}{2} = \frac{π}{4} + 2 πn, 2 θ - \frac{π}{2} = \frac{7 π}{4} + 2 πn

Solve

2 θ - \frac{π}{2} = \frac{π}{4} + 2 πn : θ = πn + \frac{3 π}{8}

Solve

2 θ - \frac{π}{2} = \frac{7 π}{4} + 2 πn : θ = πn + \frac{9 π}{8}

θ = πn + \frac{3 π}{8}, θ = πn + \frac{9 π}{8}

tan^{3} (x) + tan^{2} (x) - 3 tan (x) = 3

cos (x) = \frac{7}{9}

2 csc (x) + 3 = 0

sin (- x) = \frac{2}{2}

4 tan^{2} (θ) = 12

What is the general solution for cos(2θ-pi/2)=(sqrt(2))/2 ?
The general solution for cos(2θ-pi/2)=(sqrt(2))/2 is θ=pin+(3pi)/8 ,θ=pin+(9pi)/8