What is the general solution for sin^2(x)=-3sin(x)+4 ?

The general solution for sin^2(x)=-3sin(x)+4 is x= pi/2+2pin

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sin^2(x)=-3sin(x)+4

sin^{2} (x) = - 3 sin (x) + 4

x = \frac{π}{2} + 2 πn

Solution steps

sin^{2} (x) = - 3 sin (x) + 4

Solve by substitution

sin (x) = 1, sin (x) = - 4

sin (x) = 1 : x = \frac{π}{2} + 2 πn

sin (x) = - 4 :

No Solution

Combine all the solutions

x = \frac{π}{2} + 2 πn

tan^{2} (x) csc (x) = tan^{2} (x)

12.3 = 2.3 sin (24 x) + 14.1

7 sec^{2} (x) - 7 = 0

- 5 cos^{2} (θ) - 9 sin (θ) + 8 = - sin (θ)

2 sin (3 θ) + 2 = 0

What is the general solution for sin^2(x)=-3sin(x)+4 ?
The general solution for sin^2(x)=-3sin(x)+4 is x= pi/2+2pin