What is the general solution for sin(2x-pi/4)=0 ?

The general solution for sin(2x-pi/4)=0 is x=pin+pi/8 ,x=pin+pi/2+pi/8

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sin(2x-pi/4)=0

sin (2 x - \frac{π}{4}) = 0

x = πn + \frac{π}{8}, x = πn + \frac{π}{2} + \frac{π}{8}

Solution steps

sin (2 x - \frac{π}{4}) = 0

General solutions for

sin (2 x - \frac{π}{4}) = 0

2 x - \frac{π}{4} = 0 + 2 πn, 2 x - \frac{π}{4} = π + 2 πn

Solve

2 x - \frac{π}{4} = 0 + 2 πn : x = πn + \frac{π}{8}

Solve

2 x - \frac{π}{4} = π + 2 πn : x = πn + \frac{π}{2} + \frac{π}{8}

x = πn + \frac{π}{8}, x = πn + \frac{π}{2} + \frac{π}{8}

7 sin^{2} (θ) - 4 sin (θ) = 3

tan (θ) - cot (θ) = 0

csc^{3} (x) + csc^{2} (x) = \frac{4}{3} csc (x) + \frac{4}{3}

6 sec^{2} (x) tan (x) = 12 tan (x)

cos (θ) + cos (2 θ) = 0

What is the general solution for sin(2x-pi/4)=0 ?
The general solution for sin(2x-pi/4)=0 is x=pin+pi/8 ,x=pin+pi/2+pi/8