What is the general solution for cos(pi/4-x)=1,0<= x<= 2pi ?

The general solution for cos(pi/4-x)=1,0<= x<= 2pi is x= pi/4

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cos(pi/4-x)=1,0<= x<= 2pi

cos (\frac{π}{4} - x) = 1, 0 \leq x \leq 2 π

x = \frac{π}{4}

Solution steps

cos (\frac{π}{4} - x) = 1, 0 \leq x \leq 2 π

General solutions for

cos (\frac{π}{4} - x) = 1

\frac{π}{4} - x = 0 + 2 πn

Solve

\frac{π}{4} - x = 0 + 2 πn : x = - 2 πn + \frac{π}{4}

x = - 2 πn + \frac{π}{4}

Solutions for the range

0 \leq x \leq 2 π

x = \frac{π}{4}

sec (θ) = 5

sin^{4} (θ) - cos^{4} (θ) = 0

9 + 9 sin (θ) = 6 cos^{2} (θ)

cot (x) = \frac{1}{2}

sec (t) = 3

What is the general solution for cos(pi/4-x)=1,0<= x<= 2pi ?
The general solution for cos(pi/4-x)=1,0<= x<= 2pi is x= pi/4