What is the general solution for sin(3θ)=(sqrt(2))/2 ?

The general solution for sin(3θ)=(sqrt(2))/2 is θ= pi/(12)+(2pin)/3 ,θ= pi/4+(2pin)/3

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sin(3θ)=(sqrt(2))/2

sin (3 θ) = \frac{2}{2}

θ = \frac{π}{12} + \frac{2 πn}{3}, θ = \frac{π}{4} + \frac{2 πn}{3}

Solution steps

sin (3 θ) = \frac{2}{2}

General solutions for

sin (3 θ) = \frac{2}{2}

3 θ = \frac{π}{4} + 2 πn, 3 θ = \frac{3 π}{4} + 2 πn

Solve

3 θ = \frac{π}{4} + 2 πn : θ = \frac{π}{12} + \frac{2 πn}{3}

Solve

3 θ = \frac{3 π}{4} + 2 πn : θ = \frac{π}{4} + \frac{2 πn}{3}

θ = \frac{π}{12} + \frac{2 πn}{3}, θ = \frac{π}{4} + \frac{2 πn}{3}

(tan^{2} (θ) - 9) (2 cos (θ) + 1) = 0

2 sin (x) + cos (x) = 1

sin (θ) cos (θ) = - \frac{1}{2}

2 cos^{2} (x) - 3 cos (2 x) = 0

16 cos^{2} (x) = 4

What is the general solution for sin(3θ)=(sqrt(2))/2 ?
The general solution for sin(3θ)=(sqrt(2))/2 is θ= pi/(12)+(2pin)/3 ,θ= pi/4+(2pin)/3