What is the general solution for cos^2(θ)=sin^2(θ) ?

The general solution for cos^2(θ)=sin^2(θ) is θ= pi/4+pin,θ=(3pi)/4+pin

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cos^2(θ)=sin^2(θ)

cos^{2} (θ) = sin^{2} (θ)

θ = \frac{π}{4} + πn, θ = \frac{3 π}{4} + πn

Solution steps

cos^{2} (θ) = sin^{2} (θ)

Subtract

sin^{2} (θ)

from both sides

cos^{2} (θ) - sin^{2} (θ) = 0

Rewrite using trig identities

cos (2 θ) = 0

General solutions for

cos (2 θ) = 0

2 θ = \frac{π}{2} + 2 πn, 2 θ = \frac{3 π}{2} + 2 πn

Solve

2 θ = \frac{π}{2} + 2 πn : θ = \frac{π}{4} + πn

Solve

2 θ = \frac{3 π}{2} + 2 πn : θ = \frac{3 π}{4} + πn

θ = \frac{π}{4} + πn, θ = \frac{3 π}{4} + πn

csc (t) = \frac{1}{4}

sin (θ) = 0.21

csc (t) = sec (t)

- 2 sin^{2} (x) = sin (x) - 1

cos (4 θ) - cos (6 θ) = 0

What is the general solution for cos^2(θ)=sin^2(θ) ?
The general solution for cos^2(θ)=sin^2(θ) is θ= pi/4+pin,θ=(3pi)/4+pin