What is the general solution for 2cos(t)+1=0 ?

The general solution for 2cos(t)+1=0 is t=(2pi)/3+2pin,t=(4pi)/3+2pin

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2cos(t)+1=0

2 cos (t) + 1 = 0

t = \frac{2 π}{3} + 2 πn, t = \frac{4 π}{3} + 2 πn

Solution steps

2 cos (t) + 1 = 0

Move

1

to the right side

2 cos (t) = - 1

Divide both sides by

2

cos (t) = - \frac{1}{2}

General solutions for

cos (t) = - \frac{1}{2}

t = \frac{2 π}{3} + 2 πn, t = \frac{4 π}{3} + 2 πn

sin (3 x) = \frac{1}{2}

tan^{2} (θ) = - tan (θ)

sec (θ) = - \frac{2}{3}

tan (θ) = \frac{8}{12}

sin (t) + cos (t) = 0

What is the general solution for 2cos(t)+1=0 ?
The general solution for 2cos(t)+1=0 is t=(2pi)/3+2pin,t=(4pi)/3+2pin