What is the general solution for cos(2x)cos(x)-sin(2x)sin(x)=0 ?

The general solution for cos(2x)cos(x)-sin(2x)sin(x)=0 is x= pi/6+(2pin)/3 ,x= pi/2+(2pin)/3

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cos(2x)cos(x)-sin(2x)sin(x)=0

cos (2 x) cos (x) - sin (2 x) sin (x) = 0

x = \frac{π}{6} + \frac{2 πn}{3}, x = \frac{π}{2} + \frac{2 πn}{3}

Solution steps

cos (2 x) cos (x) - sin (2 x) sin (x) = 0

Rewrite using trig identities

cos (2 x + x) = 0

General solutions for

cos (2 x + x) = 0

2 x + x = \frac{π}{2} + 2 πn, 2 x + x = \frac{3 π}{2} + 2 πn

Solve

2 x + x = \frac{π}{2} + 2 πn : x = \frac{π}{6} + \frac{2 πn}{3}

Solve

2 x + x = \frac{3 π}{2} + 2 πn : x = \frac{π}{2} + \frac{2 πn}{3}

x = \frac{π}{6} + \frac{2 πn}{3}, x = \frac{π}{2} + \frac{2 πn}{3}

sin (a) = 0.6

sin (2 t) = - 1

tan (θ) = 8

5 cos (x) + 3 = 0

sin (\frac{2 x}{3}) = 0

What is the general solution for cos(2x)cos(x)-sin(2x)sin(x)=0 ?
The general solution for cos(2x)cos(x)-sin(2x)sin(x)=0 is x= pi/6+(2pin)/3 ,x= pi/2+(2pin)/3