What is the general solution for 5tan(θ)+9=0 ?

The general solution for 5tan(θ)+9=0 is θ=-1.06369…+pin

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5tan(θ)+9=0

5 tan (θ) + 9 = 0

θ = - 1.06369 \dots + πn

Solution steps

5 tan (θ) + 9 = 0

Move

9

to the right side

5 tan (θ) = - 9

Divide both sides by

5

tan (θ) = - \frac{9}{5}

Apply trig inverse properties

θ = arctan (- \frac{9}{5}) + πn

Show solutions in decimal form

θ = - 1.06369 \dots + πn

3 sin (θ) = 3 sin (θ) + 3 cos (θ) + 3 sin (θ)

2 sin^{2} (x) - 3 sin (x) = 2

tan (x + π) + 2 sin (x + π) = 0, 0 \leq x \leq 2 π

sin (a) + 3 cos (a) = 0

22 cos (θ) + 3 = 5

What is the general solution for 5tan(θ)+9=0 ?
The general solution for 5tan(θ)+9=0 is θ=-1.06369…+pin