What is the general solution for tan(θ)+12=2tan(θ)+11 ?

The general solution for tan(θ)+12=2tan(θ)+11 is θ= pi/4+pin

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

tan(θ)+12=2tan(θ)+11

tan (θ) + 12 = 2 tan (θ) + 11

θ = \frac{π}{4} + πn

Solution steps

tan (θ) + 12 = 2 tan (θ) + 11

Solve by substitution

tan (θ) = 1

tan (θ) = 1 : θ = \frac{π}{4} + πn

Combine all the solutions

θ = \frac{π}{4} + πn

8 sin (x) = 8 tan (x)

9 cot^{2} (x) - 16 = 0

sin (2 x) csc (x) = 1

tan (θ) = 21

2 cos^{2} (t) + cos (t) - 1 = 0

What is the general solution for tan(θ)+12=2tan(θ)+11 ?
The general solution for tan(θ)+12=2tan(θ)+11 is θ= pi/4+pin