What is the general solution for -cos(x)+sin(x)=0 ?

The general solution for -cos(x)+sin(x)=0 is x= pi/4+pin

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-cos(x)+sin(x)=0

- cos (x) + sin (x) = 0

x = \frac{π}{4} + πn

Solution steps

- cos (x) + sin (x) = 0

Rewrite using trig identities

- 1 + tan (x) = 0

Move

1

to the right side

tan (x) = 1

General solutions for

tan (x) = 1

x = \frac{π}{4} + πn

cos^{4} (2 x) - sin^{4} (2 x) = 1

sin (x) tan (x - 3 0^{\circ}) = 0

- 4 tan^{2} (θ) = - 1

2 cos^{2} (x) + 5 sin (x) + 1 = 0

\frac{125}{sin ( 11 0 ^{\circ} )} = \frac{100}{sin ( b )}

What is the general solution for -cos(x)+sin(x)=0 ?
The general solution for -cos(x)+sin(x)=0 is x= pi/4+pin