What is the general solution for solvefor y,x=sec(1/y) ?

The general solution for solvefor y,x=sec(1/y) is y= 1/(arcsec(x)+2pin),y= 1/(-arcsec(x)+2pin)

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solvefor y,x=sec(1/y)

solve for

y, x = sec (\frac{1}{y})

y = \frac{1}{arcsec ( x ) + 2 πn}, y = \frac{1}{- arcsec ( x ) + 2 πn}

Solution steps

x = sec (\frac{1}{y})

Switch sides

sec (\frac{1}{y}) = x

Apply trig inverse properties

\frac{1}{y} = arcsec (x) + 2 πn, \frac{1}{y} = - arcsec (x) + 2 πn

Solve

\frac{1}{y} = arcsec (x) + 2 πn : y = \frac{1}{arcsec ( x ) + 2 πn}

Solve

\frac{1}{y} = - arcsec (x) + 2 πn : y = \frac{1}{- arcsec ( x ) + 2 πn}

y = \frac{1}{arcsec ( x ) + 2 πn}, y = \frac{1}{- arcsec ( x ) + 2 πn}

sin (x) = \frac{7}{10}

sin (x) = \frac{7}{11}

2 sec^{2} (x) = 3 tan (x) + 1

2 sec (t) = tan^{2} (t) + 1

2 sin (x) - 2 cos (x) = 3

What is the general solution for solvefor y,x=sec(1/y) ?
The general solution for solvefor y,x=sec(1/y) is y= 1/(arcsec(x)+2pin),y= 1/(-arcsec(x)+2pin)