What is the general solution for 2cos(2θ)=-sqrt(3) ?

The general solution for 2cos(2θ)=-sqrt(3) is θ=(5pi)/(12)+pin,θ=(7pi)/(12)+pin

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2cos(2θ)=-sqrt(3)

2 cos (2 θ) = - 3

θ = \frac{5 π}{12} + πn, θ = \frac{7 π}{12} + πn

Solution steps

2 cos (2 θ) = - 3

Divide both sides by

2

cos (2 θ) = - \frac{3}{2}

General solutions for

cos (2 θ) = - \frac{3}{2}

2 θ = \frac{5 π}{6} + 2 πn, 2 θ = \frac{7 π}{6} + 2 πn

Solve

2 θ = \frac{5 π}{6} + 2 πn : θ = \frac{5 π}{12} + πn

Solve

2 θ = \frac{7 π}{6} + 2 πn : θ = \frac{7 π}{12} + πn

θ = \frac{5 π}{12} + πn, θ = \frac{7 π}{12} + πn

10 cos^{2} (x) + 11 cos (x) + 3 = 0

4 csc (x) - 5 = 3

sin (x) + 1 = 2 sin (x)

1 - 2 sin^{2} (x) - sin (x) = 0

2 sin (x) cos (x) = 3 cos (x)

What is the general solution for 2cos(2θ)=-sqrt(3) ?
The general solution for 2cos(2θ)=-sqrt(3) is θ=(5pi)/(12)+pin,θ=(7pi)/(12)+pin