What is the general solution for 15arcsin(x)=5pi ?

The general solution for 15arcsin(x)=5pi is x=(sqrt(3))/2

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15arcsin(x)=5pi

15 arcsin (x) = 5 π

x = \frac{3}{2}

Solution steps

15 arcsin (x) = 5 π

Divide both sides by

15

arcsin (x) = \frac{π}{3}

Apply trig inverse properties

x = \frac{3}{2}

2 sin^{2} (x) - sin (x) = 0, 0 \leq x < 2 π

sin (x) = \frac{3}{7}

2 sin (θ) + 6 = - 3 + 6

sin (\frac{x}{2} - \frac{π}{3}) = \frac{1}{2}, 0 \leq x \leq 2 π

4 cot (x) + 1 = 0

What is the general solution for 15arcsin(x)=5pi ?
The general solution for 15arcsin(x)=5pi is x=(sqrt(3))/2