What is the general solution for cosh(x)=4 ?

The general solution for cosh(x)=4 is x=ln(4+sqrt(15)),x=ln(4-sqrt(15))

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cosh(x)=4

cosh (x) = 4

x = ln (4 + 15), x = ln (4 - 15)

Solution steps

cosh (x) = 4

Rewrite using trig identities

\frac{e ^{x} + e ^{- x}}{2} = 4

\frac{e ^{x} + e ^{- x}}{2} = 4 : x = ln (4 + 15), x = ln (4 - 15)

x = ln (4 + 15), x = ln (4 - 15)

2 cos^{2} (θ) + 3 cos (θ) - 2 = 0

12 (1 - cos (θ)) = sin^{2} (θ)

sin (\frac{1}{6} x) = 0

2 sin (x - \frac{π}{6}) = cos (x - \frac{π}{3})

- 3 sin^{2} (θ) + 5 sin (θ) - 1 = 1

What is the general solution for cosh(x)=4 ?
The general solution for cosh(x)=4 is x=ln(4+sqrt(15)),x=ln(4-sqrt(15))