What is the general solution for sin^2(x)-6cos(x)+6=0 ?

The general solution for sin^2(x)-6cos(x)+6=0 is x=2pin

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sin^2(x)-6cos(x)+6=0

sin^{2} (x) - 6 cos (x) + 6 = 0

x = 2 πn

Solution steps

sin^{2} (x) - 6 cos (x) + 6 = 0

Rewrite using trig identities

7 - cos^{2} (x) - 6 cos (x) = 0

Solve by substitution

cos (x) = - 7, cos (x) = 1

cos (x) = - 7 :

No Solution

cos (x) = 1 : x = 2 πn

Combine all the solutions

x = 2 πn

cos (x) = \frac{14.3}{19}

- 12 sin (x) = 0

3 cot^{2} (x) - 5 = - 4

25 cot^{2} (x) - 16 = 0

- 9 cos^{2} (θ) + 9 = 16 sin (θ) - 7

What is the general solution for sin^2(x)-6cos(x)+6=0 ?
The general solution for sin^2(x)-6cos(x)+6=0 is x=2pin