What is the general solution for 4sin(θ)-2sqrt(2)=0 ?

The general solution for 4sin(θ)-2sqrt(2)=0 is θ= pi/4+2pin,θ=(3pi)/4+2pin

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

4sin(θ)-2sqrt(2)=0

4 sin (θ) - 22 = 0

θ = \frac{π}{4} + 2 πn, θ = \frac{3 π}{4} + 2 πn

Degrees

θ = 4 5^{\circ} + 36 0^{\circ} n, θ = 13 5^{\circ} + 36 0^{\circ} n

Solution steps

4 sin (θ) - 22 = 0

Move

22

to the right side

4 sin (θ) - 22 = 0

Add

22

to both sides

4 sin (θ) - 22 + 22 = 0 + 22

Simplify

4 sin (θ) = 22

4 sin (θ) = 22

Divide both sides by

4

4 sin (θ) = 22

Divide both sides by

4

\frac{4 sin ( θ )}{4} = \frac{2 2}{4}

Simplify

sin (θ) = \frac{2}{2}

sin (θ) = \frac{2}{2}

General solutions for

sin (θ) = \frac{2}{2}

sin (x)

periodicity table with

2 πn

cycle:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} sin (x) 0 \frac{1}{2} \frac{2}{2} \frac{3}{2} 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} sin (x) 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2}

θ = \frac{π}{4} + 2 πn, θ = \frac{3 π}{4} + 2 πn

θ = \frac{π}{4} + 2 πn, θ = \frac{3 π}{4} + 2 πn

sec (θ) = \frac{2}{3}

3 cos (2 θ) - 5 sin (θ) - 9 = - 5

tan (x) = 1, 0 \leq x \leq 2 π

csc (θ) = - 2, π < θ < 3 π^{2} t h (θ, t) e n, cot (θ)

sin (θ) = 0.9

What is the general solution for 4sin(θ)-2sqrt(2)=0 ?
The general solution for 4sin(θ)-2sqrt(2)=0 is θ= pi/4+2pin,θ=(3pi)/4+2pin