What is the general solution for -14cos(θ)=-7sqrt(3) ?

The general solution for -14cos(θ)=-7sqrt(3) is θ= pi/6+2pin,θ=(11pi)/6+2pin

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-14cos(θ)=-7sqrt(3)

- 14 cos (θ) = - 73

θ = \frac{π}{6} + 2 πn, θ = \frac{11 π}{6} + 2 πn

Solution steps

- 14 cos (θ) = - 73

Divide both sides by

- 14

cos (θ) = \frac{3}{2}

General solutions for

cos (θ) = \frac{3}{2}

θ = \frac{π}{6} + 2 πn, θ = \frac{11 π}{6} + 2 πn

12 cos^{2} (x) = 9

9 sin (2 x) = 9 cos (x)

sec^{2} (x) + 8 tan (x) = 10

tan (5 x) = 0

4 cos^{2} (θ) - 2 = 0

What is the general solution for -14cos(θ)=-7sqrt(3) ?
The general solution for -14cos(θ)=-7sqrt(3) is θ= pi/6+2pin,θ=(11pi)/6+2pin