What is the general solution for cos(x)=0.32 ?

The general solution for cos(x)=0.32 is x=1.24506…+2pin,x=2pi-1.24506…+2pin

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cos(x)=0.32

cos (x) = 0.32

x = 1.24506 \dots + 2 πn, x = 2 π - 1.24506 \dots + 2 πn

Degrees

x = 71.33707 \dots^{\circ} + 36 0^{\circ} n, x = 288.66292 \dots^{\circ} + 36 0^{\circ} n

Solution steps

cos (x) = 0.32

Apply trig inverse properties

cos (x) = 0.32

General solutions for

cos (x) = 0.32

cos (x) = a \Rightarrow x = arccos (a) + 2 πn, x = 2 π - arccos (a) + 2 πn

x = arccos (0.32) + 2 πn, x = 2 π - arccos (0.32) + 2 πn

x = arccos (0.32) + 2 πn, x = 2 π - arccos (0.32) + 2 πn

Show solutions in decimal form

x = 1.24506 \dots + 2 πn, x = 2 π - 1.24506 \dots + 2 πn

cos (4 t) = - \frac{3}{4}, 0 \leq t \leq 2 π

cos (x) = 0.71

cos (x) = 0.28

2 sin (θ) - 3 = - 2

cos (x) + 2 sec (x) = - 3

What is the general solution for cos(x)=0.32 ?
The general solution for cos(x)=0.32 is x=1.24506…+2pin,x=2pi-1.24506…+2pin