What is the general solution for 0= 1/5 sin(5t) ?

The general solution for 0= 1/5 sin(5t) is t=(2pin)/5 ,t= pi/5+(2pin)/5

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0= 1/5 sin(5t)

0 = \frac{1}{5} sin (5 t)

t = \frac{2 πn}{5}, t = \frac{π}{5} + \frac{2 πn}{5}

Solution steps

0 = \frac{1}{5} sin (5 t)

Switch sides

\frac{1}{5} sin (5 t) = 0

Multiply both sides by

5

sin (5 t) = 0

General solutions for

sin (5 t) = 0

5 t = 0 + 2 πn, 5 t = π + 2 πn

Solve

5 t = 0 + 2 πn : t = \frac{2 πn}{5}

Solve

5 t = π + 2 πn : t = \frac{π}{5} + \frac{2 πn}{5}

t = \frac{2 πn}{5}, t = \frac{π}{5} + \frac{2 πn}{5}

tan^{2} (x) - 1 = 0, 0 \leq x < 2 π

6 sin^{2} (x) - 5 sin (x) + 1 = 0

cos (θ) + 1 = sin (θ)

2 sec^{2} (x) - 2 = 0

2 cos (2 x) = - 2

What is the general solution for 0= 1/5 sin(5t) ?
The general solution for 0= 1/5 sin(5t) is t=(2pin)/5 ,t= pi/5+(2pin)/5