What is the general solution for 2cos(x)-sin^2(x)+2=0 ?

The general solution for 2cos(x)-sin^2(x)+2=0 is x=pi+2pin

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2cos(x)-sin^2(x)+2=0

2 cos (x) - sin^{2} (x) + 2 = 0

x = π + 2 πn

Solution steps

2 cos (x) - sin^{2} (x) + 2 = 0

Rewrite using trig identities

1 + cos^{2} (x) + 2 cos (x) = 0

Solve by substitution

cos (x) = - 1

cos (x) = - 1 : x = π + 2 πn

Combine all the solutions

x = π + 2 πn

sinh (x) = 2

cos (2 t) = \frac{1}{2}

52 sin (θ) + 4 = - 1

7 sin^{2} (x) - 1 = 0

sec^{2} (x) = tan (x)

What is the general solution for 2cos(x)-sin^2(x)+2=0 ?
The general solution for 2cos(x)-sin^2(x)+2=0 is x=pi+2pin