What is the general solution for -4cos(2x)=0 ?

The general solution for -4cos(2x)=0 is x= pi/4+pin,x=(3pi)/4+pin

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-4cos(2x)=0

- 4 cos (2 x) = 0

x = \frac{π}{4} + πn, x = \frac{3 π}{4} + πn

Solution steps

- 4 cos (2 x) = 0

Divide both sides by

- 4

cos (2 x) = 0

General solutions for

cos (2 x) = 0

2 x = \frac{π}{2} + 2 πn, 2 x = \frac{3 π}{2} + 2 πn

Solve

2 x = \frac{π}{2} + 2 πn : x = \frac{π}{4} + πn

Solve

2 x = \frac{3 π}{2} + 2 πn : x = \frac{3 π}{4} + πn

x = \frac{π}{4} + πn, x = \frac{3 π}{4} + πn

x, arcsin (y) = arcsin (x) + \frac{π}{3}

t, f = cos (b t)

3 cos (x) + sin (x) = 0

3 sec (2 x) = 2

cos^{2} (x) = - \frac{1}{2}

What is the general solution for -4cos(2x)=0 ?
The general solution for -4cos(2x)=0 is x= pi/4+pin,x=(3pi)/4+pin