What is the general solution for |cos(2x)|=1 ?

The general solution for |cos(2x)|=1 is x= pi/2+pin,x=pin

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|cos(2x)|=1

∣ cos (2 x) ∣ = 1

x = \frac{π}{2} + πn, x = πn

Solution steps

∣ cos (2 x) ∣ = 1

Solve by substitution

cos (2 x) = - 1 or cos (2 x) = 1

cos (2 x) = - 1 : x = \frac{π}{2} + πn

cos (2 x) = 1 : x = πn

Combine all the solutions

x = \frac{π}{2} + πn, x = πn

sin^{3} (x) = sin^{3} (x) tan (x)

- 4 sin^{2} (θ) - 7 sin (θ) + 7 = 0

2 cos^{2} (4 x) = 1

sin (2 x) cos (x) + cos (2 x) sin (x) = \frac{1}{2}

csc^{2} (x) + 3 csc (x) + 2 = 0

What is the general solution for |cos(2x)|=1 ?
The general solution for |cos(2x)|=1 is x= pi/2+pin,x=pin