What is the general solution for cos(3x)=sin(3x) ?

The general solution for cos(3x)=sin(3x) is x= pi/(12)+(pin)/3

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cos(3x)=sin(3x)

cos (3 x) = sin (3 x)

x = \frac{π}{12} + \frac{πn}{3}

Degrees

x = 1 5^{\circ} + 6 0^{\circ} n

Solution steps

cos (3 x) = sin (3 x)

Rewrite using trig identities

cos (3 x) = sin (3 x)

Divide both sides by

cos (3 x), cos (3 x) \neq = 0

\frac{cos ( 3 x )}{cos ( 3 x )} = \frac{sin ( 3 x )}{cos ( 3 x )}

Simplify

1 = \frac{sin ( 3 x )}{cos ( 3 x )}

Use the basic trigonometric identity:

\frac{sin ( x )}{cos ( x )} = tan (x)

1 = tan (3 x)

Switch sides

tan (3 x) = 1

tan (3 x) = 1

General solutions for

tan (3 x) = 1

tan (x)

periodicity table with

πn

cycle:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} tan (x) 0 \frac{3}{3} 13 \pm \infty - 3 - 1 - \frac{3}{3}

3 x = \frac{π}{4} + πn

3 x = \frac{π}{4} + πn

Solve

3 x = \frac{π}{4} + πn : x = \frac{π}{12} + \frac{πn}{3}

3 x = \frac{π}{4} + πn

Divide both sides by

3

3 x = \frac{π}{4} + πn

Divide both sides by

3

\frac{3 x}{3} = \frac{\frac{π}{4}}{3} + \frac{πn}{3}

Simplify

\frac{3 x}{3} = \frac{\frac{π}{4}}{3} + \frac{πn}{3}

Simplify

\frac{3 x}{3} : x

\frac{3 x}{3}

Divide the numbers:

\frac{3}{3} = 1

= x

Simplify

\frac{\frac{π}{4}}{3} + \frac{πn}{3} : \frac{π}{12} + \frac{πn}{3}

\frac{\frac{π}{4}}{3} + \frac{πn}{3}

\frac{\frac{π}{4}}{3} = \frac{π}{12}

\frac{\frac{π}{4}}{3}

Apply the fraction rule:

\frac{\frac{b}{c}}{a} = \frac{b}{c \cdot a}

= \frac{π}{4 \cdot 3}

Multiply the numbers:

4 \cdot 3 = 12

= \frac{π}{12}

= \frac{π}{12} + \frac{πn}{3}

x = \frac{π}{12} + \frac{πn}{3}

x = \frac{π}{12} + \frac{πn}{3}

x = \frac{π}{12} + \frac{πn}{3}

x = \frac{π}{12} + \frac{πn}{3}

sin (t) = \frac{3}{5}

cos (2 x) + 5 cos (x) = 2

cos (5 x) = 1

cos (θ) = 0.52

2 = sin (x)

What is the general solution for cos(3x)=sin(3x) ?
The general solution for cos(3x)=sin(3x) is x= pi/(12)+(pin)/3