What is the general solution for (tan(x)+1)^2=0 ?

The general solution for (tan(x)+1)^2=0 is x=(3pi)/4+pin

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(tan(x)+1)^2=0

(tan (x) + 1)^{2} = 0

x = \frac{3 π}{4} + πn

Degrees

x = 13 5^{\circ} + 18 0^{\circ} n

Solution steps

(tan (x) + 1)^{2} = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

Solve

tan (x) + 1 = 0 : tan (x) = - 1

tan (x) + 1 = 0

Move

1

to the right side

tan (x) + 1 = 0

Subtract

1

from both sides

tan (x) + 1 - 1 = 0 - 1

Simplify

tan (x) = - 1

tan (x) = - 1

The solution to the quadratic equation is:

tan (x) = - 1

General solutions for

tan (x) = - 1

tan (x)

periodicity table with

πn

cycle:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} tan (x) 0 \frac{3}{3} 13 \pm \infty - 3 - 1 - \frac{3}{3}

x = \frac{3 π}{4} + πn

x = \frac{3 π}{4} + πn

cos (2 x) + 3 = 5 cos (x)

3 csc (θ) + 2 = 0

\frac{1}{2} - sin (x) = 0

2 sin^{2} (x) = 3 cos^{2} (x)

sin (2 x) - cos (2 x) = 1 + sin (x) - cos (x)

What is the general solution for (tan(x)+1)^2=0 ?
The general solution for (tan(x)+1)^2=0 is x=(3pi)/4+pin