What is the general solution for sin(x)=cos(x),0<= x<= 2pi ?

The general solution for sin(x)=cos(x),0<= x<= 2pi is x= pi/4 ,x=(5pi)/4

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sin(x)=cos(x),0<= x<= 2pi

sin (x) = cos (x), 0 \leq x \leq 2 π

x = \frac{π}{4}, x = \frac{5 π}{4}

Solution steps

sin (x) = cos (x), 0 \leq x \leq 2 π

Rewrite using trig identities

tan (x) = 1

General solutions for

tan (x) = 1

x = \frac{π}{4} + πn

Solutions for the range

0 \leq x \leq 2 π

x = \frac{π}{4}, x = \frac{5 π}{4}

3 cos (θ) = 0

2 sin^{2} (θ) + sin (θ) - 9 = 2 sin (θ) - 8

cos (θ) = \frac{5}{3}

- 16 sin (x) + 8 sin (2 x) = 0

csc (x) = - \frac{1}{2}

What is the general solution for sin(x)=cos(x),0<= x<= 2pi ?
The general solution for sin(x)=cos(x),0<= x<= 2pi is x= pi/4 ,x=(5pi)/4