What is the general solution for (tan(x)-1)(sqrt(3)tan(x)-1)=0 ?

The general solution for (tan(x)-1)(sqrt(3)tan(x)-1)=0 is x= pi/4+pin,x= pi/6+pin

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(tan(x)-1)(sqrt(3)tan(x)-1)=0

Solution

(tan (x) - 1) (3 tan (x) - 1) = 0

Solution

x = \frac{π}{4} + πn, x = \frac{π}{6} + πn

Degrees

x = 4 5^{\circ} + 18 0^{\circ} n, x = 3 0^{\circ} + 18 0^{\circ} n

Solution steps

(tan (x) - 1) (3 tan (x) - 1) = 0

Solving each part separately

tan (x) - 1 = 0 or 3 tan (x) - 1 = 0

tan (x) - 1 = 0 : x = \frac{π}{4} + πn

tan (x) - 1 = 0

Move

1

to the right side

tan (x) - 1 = 0

Add

1

to both sides

tan (x) - 1 + 1 = 0 + 1

Simplify

tan (x) = 1

tan (x) = 1

General solutions for

tan (x) = 1

tan (x)

periodicity table with

πn

cycle:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} tan (x) 0 \frac{3}{3} 13 \pm \infty - 3 - 1 - \frac{3}{3}

x = \frac{π}{4} + πn

x = \frac{π}{4} + πn

3 tan (x) - 1 = 0 : x = \frac{π}{6} + πn

3 tan (x) - 1 = 0

Move

1

to the right side

3 tan (x) - 1 = 0

Add

1

to both sides

3 tan (x) - 1 + 1 = 0 + 1

Simplify

3 tan (x) = 1

3 tan (x) = 1

Divide both sides by

3

3 tan (x) = 1

Divide both sides by

3

\frac{3 tan ( x )}{3} = \frac{1}{3}

Simplify

\frac{3 tan ( x )}{3} = \frac{1}{3}

Simplify

\frac{3 tan ( x )}{3} : tan (x)

\frac{3 tan ( x )}{3}

Cancel the common factor:

3

= tan (x)

Simplify

\frac{1}{3} : \frac{3}{3}

\frac{1}{3}

Multiply by the conjugate

\frac{3}{3}

= \frac{1 \cdot 3}{3 3}

1 \cdot 3 = 3

33 = 3

33

Apply radical rule:

a a = a

33 = 3

= 3

= \frac{3}{3}

tan (x) = \frac{3}{3}

tan (x) = \frac{3}{3}

tan (x) = \frac{3}{3}

General solutions for

tan (x) = \frac{3}{3}

tan (x)

periodicity table with

πn

cycle:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} tan (x) 0 \frac{3}{3} 13 \pm \infty - 3 - 1 - \frac{3}{3}

x = \frac{π}{6} + πn

x = \frac{π}{6} + πn

Combine all the solutions

x = \frac{π}{4} + πn, x = \frac{π}{6} + πn

Popular Examples

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2 sin (- 3 x - \frac{π}{4}) = 2, 0 \leq x \leq 2 π

9sin^2(θ)-9sin(θ)-2=-6sin(θ)

9 sin^{2} (θ) - 9 sin (θ) - 2 = - 6 sin (θ)

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5 cot (θ) + 3 = 0

cos(x)+1=1

cos (x) + 1 = 1

Frequently Asked Questions (FAQ)

What is the general solution for (tan(x)-1)(sqrt(3)tan(x)-1)=0 ?
The general solution for (tan(x)-1)(sqrt(3)tan(x)-1)=0 is x= pi/4+pin,x= pi/6+pin