What is the general solution for sin(x)(2sin(x)-1)=0 ?

The general solution for sin(x)(2sin(x)-1)=0 is x=2pin,x=pi+2pin,x= pi/6+2pin,x=(5pi)/6+2pin

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sin(x)(2sin(x)-1)=0

sin (x) (2 sin (x) - 1) = 0

x = 2 πn, x = π + 2 πn, x = \frac{π}{6} + 2 πn, x = \frac{5 π}{6} + 2 πn

Solution steps

sin (x) (2 sin (x) - 1) = 0

Solving each part separately

sin (x) = 0 or 2 sin (x) - 1 = 0

sin (x) = 0 : x = 2 πn, x = π + 2 πn

2 sin (x) - 1 = 0 : x = \frac{π}{6} + 2 πn, x = \frac{5 π}{6} + 2 πn

Combine all the solutions

x = 2 πn, x = π + 2 πn, x = \frac{π}{6} + 2 πn, x = \frac{5 π}{6} + 2 πn

cos (x) = \frac{1}{8}

tan (θ) = 1.5

tan (arcsin (cos (x))) = - 3

4 sin (x) cos (x) = - 3

t, x = 3 cos (t)

What is the general solution for sin(x)(2sin(x)-1)=0 ?
The general solution for sin(x)(2sin(x)-1)=0 is x=2pin,x=pi+2pin,x= pi/6+2pin,x=(5pi)/6+2pin