What is the general solution for 7sin^2(x)+14sin(x)+7=0 ?

The general solution for 7sin^2(x)+14sin(x)+7=0 is x=(3pi)/2+2pin

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7sin^2(x)+14sin(x)+7=0

7 sin^{2} (x) + 14 sin (x) + 7 = 0

x = \frac{3 π}{2} + 2 πn

Solution steps

7 sin^{2} (x) + 14 sin (x) + 7 = 0

Solve by substitution

sin (x) = - 1

sin (x) = - 1 : x = \frac{3 π}{2} + 2 πn

Combine all the solutions

x = \frac{3 π}{2} + 2 πn

tan (θ) = 17

tan (θ) = 14

cos (x) sin (x) = 4 sin (x)

cos (θ) = \frac{- 2}{2}

sin^{3} (x) = 0

What is the general solution for 7sin^2(x)+14sin(x)+7=0 ?
The general solution for 7sin^2(x)+14sin(x)+7=0 is x=(3pi)/2+2pin