What is the general solution for sin(4x)+cos(4x)=0 ?

The general solution for sin(4x)+cos(4x)=0 is x=(3pi}{16}+\frac{pin)/4

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sin(4x)+cos(4x)=0

sin (4 x) + cos (4 x) = 0

x = \frac{3 π}{16} + \frac{πn}{4}

Solution steps

sin (4 x) + cos (4 x) = 0

Rewrite using trig identities

tan (4 x) + 1 = 0

Move

1

to the right side

tan (4 x) = - 1

General solutions for

tan (4 x) = - 1

4 x = \frac{3 π}{4} + πn

Solve

4 x = \frac{3 π}{4} + πn : x = \frac{3 π}{16} + \frac{πn}{4}

x = \frac{3 π}{16} + \frac{πn}{4}

cos (x) sin (x) - sin (x) = 0

sin (x) = \frac{π}{2}

sin (z) = - 5 + j^{7}

2 cos^{2} (θ) + 5 cos (θ) + 2 = 0

sec^{2} (x) + tan (x) = 0

What is the general solution for sin(4x)+cos(4x)=0 ?
The general solution for sin(4x)+cos(4x)=0 is x=(3pi}{16}+\frac{pin)/4